import json
from selenium.webdriver.chrome.webdriver import WebDriver
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities

chromedriver_path = "YOUR/PATH/TO/chromedriver.exe"
url = "https://selenium-python.readthedocs.io/api.html"
capabilities = DesiredCapabilities.CHROME.copy()
capabilities['goog:loggingPrefs'] = {'performance': 'ALL'}

browser = WebDriver(chromedriver_path, desired_capabilities=capabilities)

browser.get(url)
logs = browser.get_log('performance')

Option 1: if you just want to return the status code under the assumption that the page you want the status code from… exists in the log containing 'text/html content type

def get_status(logs):
    for log in logs:
        if log['message']:
            d = json.loads(log['message'])
            try:
                content_type = 'text/html' in d['message']['params']['response']['headers']['content-type']
                response_received = d['message']['method'] == 'Network.responseReceived'
                if content_type and response_received:
                    return d['message']['params']['response']['status']
            except:
                pass

Usage:

>>> get_status(logs)
200

Option 2: if you wanted to see all status codes in the relevant logs

def get_status_codes(logs):
    statuses = []
    for log in logs:
        if log['message']:
            d = json.loads(log['message'])
            if d['message'].get('method') == "Network.responseReceived":
                statuses.append(d['message']['params']['response']['status'])
    return statuses

Usage:

>>> get_status_codes(logs)
[200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200, 200]

Note 1: much of this is based on @Stefan Matei answer, however, a few things have changed between Chrome versions and I provide an idea of how to parse the logs.

Note 2: ['content-type'] Not fully reliable. Casing can change. Inspect for your use-case.